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The triangle has angle measures $2^{\circ}\;,\;\;89^{\circ}\;,\;\;89^{\circ}$
Solution CiP
If $x^{\circ},\;y^{\circ},\;z^{\circ}$ are the angles of this triangle, then :
$x^{\circ}\;,\;y^{\circ},\;z^{\circ}\;<90^{\circ}\;\;and\;\;x^{\circ}+y^{\circ}+z^{\circ}=180^{\circ} \tag{1}$
Being prime numbers, if they were all odd then their sum would be odd. We contradict (1). So one of the numbers, let's say $z^{\circ}$ is $2^{\circ}$. Then the second condition in (1) becomes :
$x^{\circ}+y^{\circ}=178^{\circ} \tag{2}$
An obvious solution for (2) , which meets the requirements of the problem, is $x^{\circ}=y^{\circ}=89^{\circ}$. This triangle is isosceles.
$x^{\circ}\underset{(1)}{<}89^{\circ}\Rightarrow y\underset{(2)}{=}178^{\circ}-x^{\circ}>89^{\circ}$. And we can still have $y^{\circ}=90^{\circ}$ , which violates all the requirements.
$\blacksquare$

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