O C O R E C T A R E Necesară // A Necessary Correction

 CORECTAREA în ceea ce o privește pe EA 

este una din cele mai grele probleme. 

Vreau să mă raportez la EA altfel...

              Regarding problem  E : 17561, which was solved on the new blog, a few clarifications are in order.

First, for angle $\widehat{ ADC}$ to be  $45^{\circ}$ , $\hat{C}$  must be greater than  $45^{\circ}$ ; consequently,

$\hat{B}\leqslant 45^{\circ}$  , making the relationship  $AB = 2\cdot AC$ possible (see the figure above, with slightly modified notation).

     Secondly, the problem can be solved without relying on concepts regarding similarity, which are covered in the Romanian curriculum in the 7th grade.

(I redrew it at a more reasonable scale compared to the recently mentioned blog.)

 A solution suitable for the 6th-grade level can be provided.

      Thirdly, to avoid the concept of a parallelogram—which also belongs to the 7th-grade curriculum—we consider the following LEMMA; I would have liked to incorporate it into another   GEOMETRIC OBJECT , but as I mentioned, I have other, more difficult problems to deal with now.

(va urma)